Multinomial coefficient (k1+k2+…)
Multinomial coefficient (k1+k2+…)! / (k1! k2! …) — the number of ways to partition n = Σki items into labelled groups of the given sizes. The sum must be ≤ 20000.
by combinatorics.openverbs.com · discovered, not yet claimed by its owner · updated 2026-10-02
Mirrored from Coinbase's public x402 Bazaar. The description is the provider's own text and has not been reviewed here; the payment requirements are copied as published.
What it does
Multinomial coefficient (k1+k2+…)! / (k1! k2! …) — the number of ways to partition n = Σki items into labelled groups of the given sizes. The sum must be ≤ 20000.
Tags: multinomial coefficient · compute multinomial · partition items into groups · labelled group count · multinomial api · bazaar
Call contract
- Method
- POST
- Input
- json
- Output
- json
- Last paid call
- 2026-10-02
{
"groups": [
"42"
]
}Use with an agent
- Discover. Agents find this listing with
GET https://bazaar.saylorinnovations.com/discovery/search?query=…, the MCP toolsearch_resources, or/discovery/resources. - Inspect. Fetch
/resources/41835.jsonfor the price and payment options. - Pay. Call
GET https://combinatorics.openverbs.com/v1/multinomial. The provider answers402with its payment requirements. An x402 client signs one of the options below and retries withPAYMENT-SIGNATURE. - Execute. The provider returns
200with the data. Agent Bazaar is not in the request path and never sees your payment.
For humans
You don't need an account or an API key; you need a wallet holding a small amount of USDC on Base, and an x402-capable client (see the examples below). Call the endpoint unpaid first to see exactly what it asks for.
Pricing & payment
- Price
- $0.004 / request
- Protocol
- x402 v2
- Auth
- No account or API key. Pay per request.
- Networks
- Base
- Demand
- 1 calls · 1 unique payers in 30d (public x402 Bazaar data)
x402 payment requirements
| Scheme | Network | Asset | Amount | Pay to | Timeout |
|---|---|---|---|---|---|
| exact | Base eip155:8453 | USDC | $0.004 | 0xb3f4de103F34b99f0Da19B4F16D6B53a14C2194A | 300s |
accepts[] (raw JSON)
[
{
"scheme": "exact",
"network": "eip155:8453",
"payTo": "0xb3f4de103F34b99f0Da19B4F16D6B53a14C2194A",
"asset": "0x833589fCD6eDb6E08f4c7C32D4f71b54bdA02913",
"amount": "4000",
"amountUsd": 0.004,
"maxTimeoutSeconds": 300
}
]Examples
curl -X POST 'https://combinatorics.openverbs.com/v1/multinomial' -H 'Content-Type: application/json' --data '{"groups":["42"]}'
# -> 402 Payment Required; read PAYMENT-REQUIRED
# retry the identical request with PAYMENT-SIGNATUREconst res = await fetch("https://combinatorics.openverbs.com/v1/multinomial", {
"method": "POST",
"headers": {
"content-type": "application/json"
},
"body": "{\"groups\":[\"42\"]}"
});
if (res.status === 402) {
const { accepts } = await res.json();
// pay one of accepts[] via an x402 client, then retry with the payment header
}import httpx
import json
res = httpx.request("POST", "https://combinatorics.openverbs.com/v1/multinomial", json=json.loads("{\"groups\":[\"42\"]}"))
if res.status_code == 402:
accepts = res.json()["accepts"]
# pay one of accepts[] via an x402 client, then retry with the payment headerDetails
- Provider
- combinatorics.openverbs.com
- Endpoint
- https://combinatorics.openverbs.com/v1/multinomial
- Machine-readable
/resources/41835.json